Is there a way to get the entities with all the attributes in one query?

TypeQL
1

Hey team,

I’m struggling to get all the relations with attributes and without them in one query. Now it looks like I really need two:
match $x sub relation; , match $x sub relation; $x owns $attr; and union them in the client code.

Is there an expression to do it in one query or is this a language limitation for now?

2

Wouldn’t match $x sub relation; return both relations with and without attributes?

I’d expect:
match $x sub relation; $x owns $attr; to return only those with attributes.
match $x sub relation; not {$x owns $attr;}; to return only those with attributes.

3

Wouldn’t match $x sub relation; return both relations with and without attributes?

Yes it would, but it won’t return any attributes at all. Speaking about union I meant that you should union list of all the relations and list of relations with attributes.

E.g.:

  • rel1
  • rel2
  • rel3
    UNION
  • rel1 owns name, date
4

Right now a match query always returns a “fixed size” of answers that is returned. As such, we don’t currently support returning one answer that contains a relation $x and another answer that contains $x and $attr…
With the proposed introduction of optionals this kind of thing will be possible: Allow retrieving attributes optionally, without filtering the query · Issue #6322 · vaticle/typedb · GitHub